(4x+3)(2x^2-5x-3)=0

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Solution for (4x+3)(2x^2-5x-3)=0 equation:


Simplifying
(4x + 3)(2x2 + -5x + -3) = 0

Reorder the terms:
(3 + 4x)(2x2 + -5x + -3) = 0

Reorder the terms:
(3 + 4x)(-3 + -5x + 2x2) = 0

Multiply (3 + 4x) * (-3 + -5x + 2x2)
(3(-3 + -5x + 2x2) + 4x * (-3 + -5x + 2x2)) = 0
((-3 * 3 + -5x * 3 + 2x2 * 3) + 4x * (-3 + -5x + 2x2)) = 0
((-9 + -15x + 6x2) + 4x * (-3 + -5x + 2x2)) = 0
(-9 + -15x + 6x2 + (-3 * 4x + -5x * 4x + 2x2 * 4x)) = 0
(-9 + -15x + 6x2 + (-12x + -20x2 + 8x3)) = 0

Reorder the terms:
(-9 + -15x + -12x + 6x2 + -20x2 + 8x3) = 0

Combine like terms: -15x + -12x = -27x
(-9 + -27x + 6x2 + -20x2 + 8x3) = 0

Combine like terms: 6x2 + -20x2 = -14x2
(-9 + -27x + -14x2 + 8x3) = 0

Solving
-9 + -27x + -14x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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